1Z0-071 VALID EXAM SYLLABUS - VALID 1Z0-071 EXAM BOOTCAMP

1z0-071 Valid Exam Syllabus - Valid 1z0-071 Exam Bootcamp

1z0-071 Valid Exam Syllabus - Valid 1z0-071 Exam Bootcamp

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Oracle Database SQL Sample Questions (Q310-Q315):

NEW QUESTION # 310
Which three statements are true about performing Data Manipulation Language (DML) operations on a view in an Oracle Database?

  • A. Insert statements can always be done on a table through a view.
  • B. Views cannot be used to add or modify rows in an underlying table if the defining query of the view contains the DISTINCT keyword.
  • C. Views cannot be used to add or modify rows in an underlying table if the defining query of the view contains aggregating functions.
  • D. The WITH CHECK clause has no effect when deleting rows from the underlying table through the view.
  • E. Views cannot be used to add rows to an underlying table if the table has columns with NOT NULL constraints lacking default values which are not referenced in the defining query of the view.
  • F. Views cannot be used to query rows from an underlying table if the table has a PRIMARY KEY and the PRIMARY KEY columns are not referenced in the defining query of the view.

Answer: C,E,F


NEW QUESTION # 311
Examine the data in the CUST_NAME column of the CUSTOMERS table.

You want to extract only those customer names that have three names and display the * symbol in place of the first name as follows:

Which two queries give the required output?

  • A. SELECT LPAD(SUBSTR(cust_name ' ')),LENGTH(cust_name) - INSTR(cust_name, ' '), '*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',1,-2)<>0;
  • B. SELECT LPAD(SUBSTR(cust_name ' ')),LENGTH(cust_name) - INSTR(cust_name, ' '), '*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',1,2)<>0;
  • C. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',1,2)<>0;
  • D. SELECT LPAD(SUBSTR(cust_name, INSTR(cust_name, ' ')),LENGTH(cust_name),'*') "CUST NAME"FROM customersWHERE INSTR(cust_name, ' ',-1,2)<>0;

Answer: C,D


NEW QUESTION # 312
View the Exhibit and examine the details of PRODUCT_INFORMATION table.
PRODUCT_NAME
CATEGORY_ID
SUPPLIER_ID
Inkjet C/8/HQ
12
102094
Inkjet C/4
12
102090
LaserPro 600/6/BW
12
102087
LaserPro 1200/8/BW
12
102099
Inkjet B/6
12
102096
Industrial 700/ID
12
102086
Industrial 600/DQ
12
102088
Compact 400/LQ
12
102087
Compact 400/DQ
12
102088
HD 12GB /R
13
102090
HD 10GB /I
13
102071
HD 12GB @7200 /SE
13
102057
HD 18.2GB @10000 /E
13
102078
HD 18.2GB @10000 /I
13
102050
HD 18GB /SE
13
102083
HD 6GB /I
13
102072
HD 8.2GB@5400
13
102093
You have the requirement to display PRODUCT_NAME from the table where the CATEGORY_ID column has values 12 or 13, and the SUPPLIER_ID column has the value
102088. You executed the following SQL statement:
SELECT product_name
FROM product_information
WHERE (category_id = 12 AND category_id = 13) AND supplier_id = 102088; Which statement is true regarding the execution of the query?

  • A. It would execute and the output would display the desired result.
  • B. It would not execute because the entire WHERE clause condition is not enclosed within the parentheses.
  • C. It would not execute because the same column has been used in both sides of the AND logical operator to form the condition.
  • D. It would execute but the output would return no rows.

Answer: D


NEW QUESTION # 313
Which three statements are true about multiple row subqueries?

  • A. They can return multiple columns.
  • B. They can contain HAVING clauses.
  • C. They can contain GROUP BY clauses.
  • D. Two or more values are always returned from the subquery.
  • E. They cannot contain a subquery.

Answer: A,C,D


NEW QUESTION # 314
Examine the description of the EMPLOYEEStable:

Which query is valid?

  • A. SELECT dept_id, MAX(AVG(salary)) FROM employees GROUP BY dept_id;
  • B. SELECT dept_id, join_date, SUM(salary) FROM employees GROUP BY dept_id,
    join_date;
  • C. SELECT dept_id, AVG(MAX(salary)) FROM employees GROUP BY dept_id;
  • D. SELECT dept_id, join_date, SUM(salary) FROM employees GROUP BY dept_id;

Answer: D


NEW QUESTION # 315
......

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